A tuning fork is hit with a force of 10 N. It vibrates to produce a sound of 50 Hz frequency. The number of vibrations made by the tuning fork in 5 sec would be _____.

100

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250

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500

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1000

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Solution

The correct option is B 250
Given
FRequency of sound wave = 50 Hz
The number of vibrations made by tuning fork is equal to frequency of the sound wave.
Thus number of vibrations made by tuning fork = 50 per second.
Total number of vibrations in 5 sec = 50 x 5 = 250 vibrations.

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