A tuning fork makes $256$ $v i b r a t i o n s / s$ in air. When velocity of sound in air is $330 m / s$ , then the wavelength of tone emitted is

1.29 m

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2.1 m

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0.5 m

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0.9 m

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Solution

The correct option is B $1.29 m$
We know
$v = n λ$
Where
$v$ is speed of sound.
$n$ is frequency.
$λ$ is wavelength.
Given
$n = 256 v i b r a t i o n s / s = 256 H z$
$v = 330 m / s$
$330 = 256 \times λ$
$λ = \frac{330}{256} = 1.29 m$

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A tuning fork makes 256 vibrations/s in air. When velocity of sound in air is 330m/s, then the wavelength of tone emitted is

The correct option is B 1.29mWe know v=nλWherev is speed of sound.n is frequency.λ is wavelength.Givenn=256vibrations/s=256Hzv=330m/s330=256×λλ=330256=1.29m

A tuning fork makes $256$ $v i b r a t i o n s / s$ in air. When velocity of sound in air is $330 m / s$ , then the wavelength of tone emitted is

The correct option is B $1.29 m$
We know
$v = n λ$
Where
$v$ is speed of sound.
$n$ is frequency.
$λ$ is wavelength.
Given
$n = 256 v i b r a t i o n s / s = 256 H z$
$v = 330 m / s$
$330 = 256 \times λ$
$λ = \frac{330}{256} = 1.29 m$