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Byju's Answer

Standard XII

Physics

Beat Frequency

A tuning fork...

Question

A tuning fork of frequency 100 when sounded together with another tuning fork of unknown frequency produces 2 beats per second. On loading the tuning fork whose frequency is not known and sounded together with a tuning fork of frequency 100 produces one beat, then the frequency of the other tuning fork is

[NCERT 1977]

102

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101

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Solution

The correct option is A
102

Suppose $n_{A}$ = known frequency = 100 Hz, $n_{B}$ = ?

x = 2 = Beat frequency, which is decreasing after loading (i.e. x $↓$ )

Unknown tuning fork is loaded so $n_{B} ↓$

Hence $n_{A} - n_{B} ↓= x ↓$ ............(i) $\to$ Wrong

$n_{B} ↓ - n_{A} = x ↓$ ............(ii) $\to$ Correct

$\Rightarrow n_{B} = n_{A} + x = 100 + 2 = 102 H z$ .

Suggest Corrections

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The correct option is A 102 Suppose nA= known frequency = 100 Hz, nB = ? x = 2 = Beat frequency, which is decreasing after loading (i.e. x↓) Unknown tuning fork is loaded so nB↓ Hence nA−nB↓=x↓ ............(i)→ Wrong nB↓−nA=x↓ ............(ii)→ Correct ⇒nB=nA+x=100+2=102 Hz.