A tuning fork of frequency 256 Hz is moving towards a well with a velocity of 5 m/s. If the speed of sound is 330 m/s, then the number of beats heard per second by a stationary observer lying between tuning fork and the wall is :
A
2
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B
4
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C
zero
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D
8
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Solution
The correct option is C zero Let nd and n′′ be the frequencies heard by the observer O coming directly from the tuning fork and after reflecting from the wall respectively.
Velocity of sound in air vsound=330m/s
Velocity of the source vsource=5m/s
Doppler effect when a source moves towards the stationary observer:
nd=n[vsoundvsound−vsource]=256[330330−5]=260Hz
Doppler effect when a source moves towards the wall:
n′=n[vsoundvsound−vsource]=256[330330−5]=260Hz
Now apparent frequency after the reflection from the wall n′′=n′=260Hz