A tuning fork of frequency 384Hz gives 6 beats in 2 seconds when sounded with another tuning fork B. What could be the frequency of B?
A
381Hz
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B
387Hz
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C
It could be either A or B
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D
None of the above
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Solution
The correct option is B It could be either A or B Since 6 beats are produced in 2 seconds. Thus beat frequency b=62=3Hz Beat frequency b=|fA−fB| ∴3=|384−fB| Thus fB=384−3=381Hz or fB=384+3=387Hz Thus frequency of B can either be 381Hz or 387Hz.