A tuning fork of frequency $580 H z$ is employed to produce transverse waves on a long rope. The distance between the nearest crests is found to be $20 c m$ . The velocity of the wave is

58 {m s}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

580 {m s}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

20 {m s}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

116 {m s}^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $116 {m s}^{- 1}$
Distance between adjacent crests equals wavelength.
$λ = 0.2 m$

$v = f λ$
$= 580 \times 0.2$
$= 116 m / s$

Suggest Corrections

Similar questions

Q. The separation between two consecutive crests in a transverse wave is

100 m

. If wave velocity is

20 m s^{- 1}

, find the frequency of wave.

Q. A rope is vibrating with frequency 20 Hz. If the velocity of the wave in the rope is

20 m s^{- 1}

, then the distance between a crest and the successive trough is ................

Q. The distance between

2^{n d}

crest and

6^{t h}

trough of a wave shown below is

24 c m

. If the wave velocity of the moving crests is

20 m s^{- 1}

, then frequency of rocking of the boat is

The figure showed the shape of part of a long string in which transverse waves are produced by attaching one end of the string to tuning fork of frequency

250 H z

. What is the velocity of the waves?

Figure shows the shape of part of a long string in which transverse waves are produced by attaching one end of the string to tuning fork of
frequency 250 Hz. What is the velocity of the waves?

Join BYJU'S Learning Program

A tuning fork of frequency 580Hz is employed to produce transverse waves on a long rope. The distance between the nearest crests is found to be 20cm. The velocity of the wave is

The correct option is D 116ms−1Distance between adjacent crests equals wavelength.λ=0.2 mv=fλ =580×0.2 =116 m/s

A tuning fork of frequency $580 H z$ is employed to produce transverse waves on a long rope. The distance between the nearest crests is found to be $20 c m$ . The velocity of the wave is

The correct option is D $116 {m s}^{- 1}$
Distance between adjacent crests equals wavelength.
$λ = 0.2 m$

$v = f λ$
$= 580 \times 0.2$
$= 116 m / s$