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Question

A tuning fork of unknown frequency when sounded with another of 256 Hz gives 4 beats/sec. When a loaded with a certain amount of wax it is found give 2 beats. The unknown frequency is

A
240 Hz
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B
250 Hz
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C
260 Hz
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D
270 Hz
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Solution

The correct option is B 260 Hz
When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - a phenomenon which is called "beating" or producing beats.
Frequency of beats is =f=|f1f2|.
Now, Unknown frequency =256±4Hz
=260 Hz or 252 Hz
When A is loaded with wax, its frequency decreases, i.e. the number of beats is decreased, Unknown frequency =260 Hz

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