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Question

A tuning fork produces 4 beats per second with another tuning fork of frequency 256 Hz. the first one is now loaded with a little wax and the beat frequency is found to increase to 6 per second. What was the original frequency of the tuning fork?

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Solution

Frequency of tuning for A:
n1=256Hz
No .of beats /sec m=4

Frequency of tuning for B:n2=??
n2=n1+m
n2=256+4=260Hz

or

n2=n1m
n2=2564= 252 Hz

Now, as it is loaded with wax, its frequency will decrease.
As it produces 6 beats per second, The original frequency must be 252 Hz.

260Hz is not possible because on decreasing the frequency, the beats per second should decrease, Which is not possible.

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