CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A tuning fork produces 4 beats per second with another tuning fork of frequency 256 Hz. the first one is now loaded with a little wax and the beat frequency is found to increase to 6 per second. What was the original frequency of the tuning fork?

Open in App
Solution

Frequency of tuning for A:
n1=256Hz
No .of beats /sec m=4

Frequency of tuning for B:n2=??
n2=n1+m
n2=256+4=260Hz

or

n2=n1m
n2=2564= 252 Hz

Now, as it is loaded with wax, its frequency will decrease.
As it produces 6 beats per second, The original frequency must be 252 Hz.

260Hz is not possible because on decreasing the frequency, the beats per second should decrease, Which is not possible.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Phase Difference and Resultant Amplitude
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon