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Question

A tuning fork produces 8 beats per second when sounded together with a fork of frequency 340 Hz. When the prongs of tuning fork C are filled a little, the number of beats produced per second decreases to 4. Find the frequency of the tuning fork C before filling its prongs.

A
332 Hz
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B
434 Hz
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C
430 Hz
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D
436 Hz
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Solution

The correct option is A 332 Hz
given :

nD= tuning fork D frequency =340Hz
nC= tuning fork C frequency=84=4 beats per second.
First nC±nD=8(before filing)
nC±nD=4(after filing)
From given condition nc±nD=8
nc±340=8
nc=340+8=348Hz
or,nc=3408=332Hz
when tuning fork C is filed then nc±nD=4
nc±340=4
nc=340+4=344Hz
or,nc=3404=336Hz
The frequency of tuning fork increases on filing. Hence nc344Hz.
If original frequency of tuning fork C is taken 332 Hz, then on filing both the value 344Hz, and 336Hz are greater.
Also it produces 4 beats per second with tuning fork D.
frequency of tuning fork C=332Hz
Hence,
option (A) is correct answer.

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