Question

A tuning fork produces sound of frequency 200 Hz. Find the time period of vibration.

Answer 1

Step 1: Given

$frequency\left(\nu \right)=$ $200Hz$

$T=timeperiod$

Step 2: Formula used

$timeperiod=$ $\frac{1}{frequency}$

i.e. $T=\frac{1}{\nu }$

Step 3: Calculation

$T=\frac{1}{\nu }$

$$\begin{gathered} T=\frac{1}{200}s \\ =0.005s \end{gathered}$$

Hence, the time period of vibration is $0.005s$.