A tuning fork sounded together with a tuning fork of frequency 256 emits two beats. On loading the tuning fork of frequency 256, the number of beats heard are 1 per second. The frequency of tuning fork is

[NCERT 1975, 81; MP PET 1985]

257

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258

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256

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254

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Solution

The correct option is D
254

$n_{A}$ = Known frquency = 256, $n_{B}$ = ?

x = 2 bps, which is decreasing after loading (i.e. x $↓)$ known tuning fork is loaded so $n_{A} ↓$

Hence $n_{A} ↓ - n_{B} = x ↓$ ............(i) $\to$ Correct

$n_{B} - n_{A} ↓= x ↓$ .............(ii) $\to$ Wrong

$\Rightarrow n_{B} = n_{A} - x = 256 - 2 = 254 H z$

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A tuning fork sounded together with a tuning fork of frequency 256 emits two beats. On loading the tuning fork of frequency 256, the number of beats heard are 1 per second. The frequency of tuning fork is [NCERT 1975, 81; MP PET 1985]

The correct option is D 254 nA = Known frquency = 256, nB = ? x = 2 bps, which is decreasing after loading (i.e. x ↓) known tuning fork is loaded so nA↓ Hence nA↓−nB=x↓ ............(i) → Correct nB−nA↓=x↓ .............(ii)→ Wrong ⇒nB=nA−x=256−2=254 Hz

A tuning fork sounded together with a tuning fork of frequency 256 emits two beats. On loading the tuning fork of frequency 256, the number of beats heard are 1 per second. The frequency of tuning fork is

[NCERT 1975, 81; MP PET 1985]