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Question

A tuning fork vibrating with a sonometer having 20 cm wire produces 5 beats per second. If the beat frequency does not change if the length of the wire is changed to 21 cm, then the frequency of the tuning fork (in Hz) must be

A
200
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B
210
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C
205
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D
215
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Solution

The correct option is C 205
Let ft be the frequency of the tuning fork.

Then, frequency of 21 cm sonometer = ft5
and frequency of 20 cm sonometer = ft+5

Frequency of sonometer vibration f=v2L

ft5=v2×21

ft+5=v2×20

(since v is going to remain constant for the same sonometer material)

Hence,

2(ft+5)20=2(ft5)21
20ft+100=21ft105
ft=205 Hz.


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