Byju's Answer

Standard XII

Physics

String Open at One End

A tuning fork...

Question

A tuning fork vibrating with a sonometer having $20 c m$ wire produces $5$ beats per second. The beat frequency does not change, if the length of the wire is changed to $21 c m$ . The frequency of tuning fork is:

200 H z

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210 H z

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205 H z

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215 H z

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Solution

The correct option is C $205 H z$
The frequency of sonometer decrease on increasing the length.
Thus $f_{1} - f_{0} = 5 = \frac{v}{2 (0.2)} - f_{0}$
and $f_{0} - f_{2} = 5 = f_{0} - \frac{v}{2 (0.21)}$
$⟹ v = 84 m / s$
Thus $f_{0} = 205 H z$

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A tuning fork vibrating with a sonometer having 20 cm wire produces 5 beats per second. The beat frequency does not change, if the length of the wire is changed to 21 cm. The frequency of tuning fork is:

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A tuning fork vibrating with a sonometer having $20 c m$ wire produces $5$ beats per second. The beat frequency does not change, if the length of the wire is changed to $21 c m$ . The frequency of tuning fork is:

The correct option is C $205 H z$
The frequency of sonometer decrease on increasing the length.
Thus $f_{1} - f_{0} = 5 = \frac{v}{2 (0.2)} - f_{0}$
and $f_{0} - f_{2} = 5 = f_{0} - \frac{v}{2 (0.21)}$
$⟹ v = 84 m / s$
Thus $f_{0} = 205 H z$