wiz-icon
MyQuestionIcon
MyQuestionIcon
7
You visited us 7 times! Enjoying our articles? Unlock Full Access!
Question

A tuning fork was sounded over the open end of an air column, and produced 4 beats/ sec when temperature of air was 20C. The tuning fork gave the lower note when the temperature gradually decreased to 5C, the tuning fork produced 3 beats per second. The frequency of the tuning fork is (in Hz).

A
27
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
14
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
34
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
63
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 14
Let v be frequency of tunning fork
At t=20°C,T=273+20=293K
n=v+4
At t=5°C,T=273.5=278K
n=v+3
Now nαTv+4v+3=29327815v=(278×4)(293×3)15v=233v14Hz

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Speed of sound
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon