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Question

A tuning fork was sounded over the open end of an air column, and produced 4 beats/ sec when temperature of air was 20C. The tuning fork gave the lower note when the temperature gradually decreased to 5C, the tuning fork produced 3 beats per second. The frequency of the tuning fork is (in Hz).

A
27
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B
14
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C
34
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D
63
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Solution

The correct option is B 14
Let v be frequency of tunning fork
At t=20°C,T=273+20=293K
n=v+4
At t=5°C,T=273.5=278K
n=v+3
Now nαTv+4v+3=29327815v=(278×4)(293×3)15v=233v14Hz

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