Question

A tuning fork with the time period of $\frac{1}{256}\text{s}$ produces a sound wave which has separation between adjacent compression and rarefaction of $0.7\text{m}$. Then, the speed of sound is

• A. $250\text{m/s}$
• B. $400\text{m/s}$
• C. $310\text{m/s}$
• D. $358\text{m/s}$

Answer 1

The correct option is D $358\text{m/s}$

Distance between adjacent compression and rarefaction is equal to half wavelength.


So, $\lambda =0.7\times 2=1.4\text{m}$
We know that velocity of sound wave is given by,
$v=\frac{\lambda }{T}$, where $\lambda$ is wavelength and $T$ is time period.
$\Rightarrow v=\frac{1.4\times 256}{1}=358\text{m/s}$