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Newton's Laws for System of Particles

A tunnel is d...

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A tunnel is dug in the earth across one of the diameter. Two masses m and 2m are dropped from two ends of tunnel. The masses collide and stick each other. They perform SHM amplitude of which is

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Q. A tunnel is dug in the earth across one of its diameter. Two masses

m

2 m

are dropped from the two ends of the tunnel. The masses collide and stick each other. They perform

S H M,

the amplitude of which is

(R =

radius of earth)

Q. A tunnel is dug n the earth across one of its diameter. Two masses 'm' & '2m' are dropped from the ends of the tunnel. The masses collide and stick to each other and performs S.H.M. Then amplitude of S.H.M. will be : [R=radius of the earth]

Q. A tunnel is dug in the earth across one of its diameters. Two masses

m

2 m

are dropped from the ends of the tunnel. If the masses collide and stick to each other and perform

S.H.M.

then amplitude of

S.H.M.

(R =

radius of the earth

)

Q. A tunnel is dug along the diameter of the earth. Two balls of mass

m

2 m

are dropped from the opposite ends of the tunnel simultaneously. They collide in the tunnel and stick to each other. If the new amplitude of their oscillation is

\frac{R}{n}

R

is earth's radius, then the value of

n

Q. Two smooth tunnels are dug from one side of the earth's surface to the other side, one along with a diameter and the other along with a chord. Now two particles are dropped from one end of each of the tunnels. Both the particles oscillate simple harmonically along the tunnels. Let

T_{1}

T_{2}

be the time periods and

v_{1}

v_{2}

be the maximum speed of the particles in the two tunnels. Then :

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