Question

A turn of radius 600 m is banked for a vehicle of mass 200 kg going with a speed of 1800 $km{h}^{-1}$. Determine the banking angle of its path.

Answer 1

The turn is banked for speed ,
v=180 $km{h}^{-1}=180\times \frac{5}{18}m{s}^{-1}=50m{s}^{-1}$
and radius r = 600m
$\because$ $tan\theta =\frac{25}{60}=\frac{50\times 50}{600\times 10}$
$\Rightarrow$ $tan\theta =\frac{25}{60}=0.417$
$\Rightarrow$Banking angle $\theta =ta{n}^{-1}\left(0.417\right)$
$\theta =22.6\left(0\right)$