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Pseudo Force

A turn table ...

Question

A turn table is rotating about the fixed vertical axis. A particle of mass $m$ is lying on a table at rest with respect to the table. An observer is standing over a block of mass $M$ moving with an acceleration $a$ . Find the magnitude of pseudo-force on a particle of mass $m$ as observed by the observer. (Given a body is subjected to an acceleration called centripetal acceleration directed towards the centre when it is rotating and is equal to $r ω^{2}$ )

m (a - r ω^{2})

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M a

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m (a + r ω^{2})

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m a

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Solution

The correct option is D $m a$
Using the concept of pseudo force in the frame of observer standing over the block, we have
acceleartion of the body of mass $m$ is $a$
$∴$ Pseudo force ${\to F}_{s} = m_{body} {\to a}_{frame of reference} = - m a^i$
Hence magnitude, $F_{s} = m a$

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The correct option is D maUsing the concept of pseudo force in the frame of observer standing over the block, we have acceleartion of the body of mass m is a ∴ Pseudo force →Fs=mbody→aframe of reference=−ma^i Hence magnitude, Fs=ma

The correct option is D $m a$
Using the concept of pseudo force in the frame of observer standing over the block, we have
acceleartion of the body of mass $m$ is $a$
$∴$ Pseudo force ${\to F}_{s} = m_{body} {\to a}_{frame of reference} = - m a^i$
Hence magnitude, $F_{s} = m a$