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Standard IX

Physics

Effect of Temperature on Speed of Sound in Gases

A turning for...

Question

A turning fork having a frequency of 480 Hz produces waves of wavelength 2.5 m, then the velocity of sound in mediums is :

\frac{6}{5} k m s^{- 1}

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1200 m s^{- 1}

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12 c m s^{- 1}

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1200 m m s^{- 1}

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Solution

The correct options are
A $\frac{6}{5} k m s^{- 1}$
B $1200 m s^{- 1}$
$V = v λ$
$= 480 \times 2.5$
$= 1200 m s^{- 1}$ (or) $\frac{6}{5} k m s^{- 1}$

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Similar questions

Q. A tuning fork having a frequency of

480 H z

produces waves of wavelength

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, then the velocity of sound in the medium is:

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denotes the speed of the sound waves produced by the first tuning fork and

v_{2}

denotes the speed of the sound waves produced by the second turning fork, then find out which of following hold true?

Q. A sound source sends waves of

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Q. The velocity of sound in a gas is 4 times that in air at the same temperature. When a tuning fork is sounded in a wave of frequency 480 and wavelength

λ_{1}

is produced. The same fork is sounded in the gas and of

λ_{2}

is the wavelength of the wave, then

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is :

A sound wave having a wavelength of 20 cm is travelling in water. If the velocity of sound in water is $1600 m s^{- 1}$ then, find the frequency of the sound wave.

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A turning fork having a frequency of 480 Hz produces waves of wavelength 2.5 m, then the velocity of sound in mediums is :

The correct options are A 65kms−1 B 1200ms−1V=vλ=480×2.5=1200ms−1 (or) 65kms−1

The correct options are
A $\frac{6}{5} k m s^{- 1}$
B $1200 m s^{- 1}$
$V = v λ$
$= 480 \times 2.5$
$= 1200 m s^{- 1}$ (or) $\frac{6}{5} k m s^{- 1}$