Question

A TV tower has a height of $100m$. The population covered by TV broadcast (the average population density around the tower is $1000/k{m}^2$) is

• A. $40\times {10}^5$
• B. $20\times {10}^6$
• C. $30\times {10}^7$
• D. $10\times {10}^4$

Answer 1

The correct option is A $40\times {10}^5$

We have the total area over which the transmission is viewed as

$A=2\pi hR$

$=2\times 3.14\times 0.1\times 6.37\times {10}^{3}k{m}^2=4000k{m}^2$

And the population density is given as $1000/k{m}^2$.

Thus, we get the population covered as $4000\times 1000=40\times {10}^5$.