Question

A TV tower has a height of 70m. If the average population density around the tower is $1000k{m}^{-2}$ , the population covered by the TV tower is ( Radius of Earth is $6.4\times {10}^{6}m$)

• A. $2.816\times {10}^6$
• B. $2.86\times {10}^9$
• C. $2.816\times {10}^3$
• D. $2.816\times {10}^{12}$

Answer 1

The correct option is A $2.816\times {10}^6$

Population Covered $=$ Population Density $\times 2\pi hR$
$=1000\times {10}^{-6}\times 2\pi \times 70\times 6.4\times {10}^6$
$=2816\times {10}^3=2.816\times {10}^6$