A twin table record revolves at 60 Rpm if the diameter of the record is 20 cm. Find the angular velocity and linear velocity of 2 apex of dust situated at 5 cm from the centre and 10 cm from the centre.

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Solution

Given,
$\begin{matrix} w = 60 R P M = 60. \frac{π}{30} = 2 π r a d / sec \end{matrix}$
Now,
Velocity of apex of dust situated at $5$ cm
$V = r w$
$\begin{matrix} V = 5 \times 2 π = 10 π m / s \end{matrix}$
Velocity of apex at $10$ cm from center.
$\begin{matrix} V = r w = 10 \times 2 π = 20 π m / s \end{matrix}$

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A twin table record revolves at 60 Rpm if the diameter of the record is 20 cm. Find the angular velocity and linear velocity of 2 apex of dust situated at 5 cm from the centre and 10 cm from the centre.

Given,w=60RPM=60.π30=2πrad/secNow,Velocity of apex of dust situated at 5cmV=rwV=5×2π=10πm/sVelocity of apex at 10cm from center.V=rw=10×2π=20πm/s