Question

A two digit natural number leaves 1 and 3 as remainders when divided by 2 and 9 respectively. If the number is multiple of 5, what is the digit at its ten's place?

• A. 2
• B. 8
• C. 7
• D. 3

Answer 1

The correct option is C

7

By applying divisibility test of 2, the digit at unit's place should be 0, 2, 4, 6, 8.

But remainder is 1 and the number is multiple of 5. Hence, the digit at unit's place will be 6 - 1 = 5

For a number to be divisible by 9, the sum of the digits should be divisible by 9.

It is given that when a number is divided by 9, the remainder is 3.

Thus, 75 is the only number which satisfy the given conditions.

Hence, 7 is the digit at ten's place.