A two digit number can be represented as.
[Consider number " $x y$ "]

x y

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10 x + y

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x^{y}

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e^{x y}

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Solution

The correct option is B $10 x + y$
Let us assume that the tens-digit is $x$ and the unit-digit is $y$ .
The value of the two-digit number will be
$= 10 \times$ tens-digit + unit-digit
$= 10 \times x + y$
$= 10 x + y$

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