A two digit number consists of 2 digits whose sum is 6. If 18 is added to the number, its digits are reversed. Find the number.
Let x and y be respectively unit and tenth digit of two-digit number then the number will
10y+x
condition 1:the sum of digits is 6 hence
x+y=6........(i)
condition 2 :when 18 is added to number 10y +x then digits are reversed
i.e
18+10y+x=10x+y
x−y=2...........(ii)
adding (i)and (ii) we get
x=4
by putting value of x in (i) or (ii) we get
y=2
Hence the number is
10y+x
=10×2+4
=24
Hence option A is correct.