A two-digit number exceeds four times the sum of its digits by $3.$ If the number is increased by $18$ , the result is the same as the number formed by interchanging the digits. Find the number.

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Solution

$L e t t h e d i g i t s b e x a n d y . 10 x + y = 4 (x + y) + 3 6 x - 3 y = 3 2 x - y = 1 10 x + y + 18 = 10 y + x 9 y - 9 x = 19 y - x = 2 x = 3 y = 5$

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A two-digit number exceeds four times the sum of its digits by 3. If the number is increased by 18, the result is the same as the number formed by interchanging the digits. Find the number.

Letthedigitsbexandy.10x+y=4(x+y)+36x−3y=32x−y=110x+y+18=10y+x9y−9x=19y−x=2x=3y=5

A two-digit number exceeds four times the sum of its digits by $3.$ If the number is increased by $18$ , the result is the same as the number formed by interchanging the digits. Find the number.

$L e t t h e d i g i t s b e x a n d y . 10 x + y = 4 (x + y) + 3 6 x - 3 y = 3 2 x - y = 1 10 x + y + 18 = 10 y + x 9 y - 9 x = 19 y - x = 2 x = 3 y = 5$