A two digit number is 5 times the sum of its digits. What is the remainder when this number is divided by 9?

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Zero

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
Zero

10a + b = 5(a + b)

10a + b = 5a + 5b ....(1)

5a = 4b

Putting 5a = 4b in (1), we get

10a + b = 4b + 5b = 9b i.e. multiple of 9.

Hence, dividing the number by 9 gives 0 as remainder.

Suggest Corrections

Similar questions

A number consists of two digits.When it is divided by the sum of its digits,the quotient is 6 with no remainder.When the number is diminished by 9, the digits are reversed.Find the number.

Q. When a two-digits number is divided by the sum of its digits, the quotient is

8

. On diminishing the ten's digit by three times the units digit, the remainder obtained is

1

. Find the number.

When two digit number is divided by the sum of its digits the quotient is 8. If the ten's digit is diminished by three times the unit's digit the remainder is 1. What is the no.?

when a two digit number is divided by the sum of its dig its ,the quotient is 8.on diminishing the tens's digit by three times the units digit the remainder obtained is 1 find the number

Q. If a certain number is divided by the sum of its two digits, the quotient is

6

and remainder is

3

. If the digits are interchanged and the resulting number is divided by the sum of the digits, then the quotient is

4

and the remainder is

9

. Find the number.

Join BYJU'S Learning Program

A two digit number is 5 times the sum of its digits. What is the remainder when this number is divided by 9?

The correct option is B Zero 10a + b = 5(a + b) 10a + b = 5a + 5b ....(1) 5a = 4b Putting 5a = 4b in (1), we get 10a + b = 4b + 5b = 9b i.e. multiple of 9. Hence, dividing the number by 9 gives 0 as remainder.

The correct option is B
Zero

10a + b = 5(a + b)

10a + b = 5a + 5b ....(1)

5a = 4b

Putting 5a = 4b in (1), we get

10a + b = 4b + 5b = 9b i.e. multiple of 9.

Hence, dividing the number by 9 gives 0 as remainder.