Let the tens digit be x and the units digit be y.
∴ Product of the digits = xy = 35............(i)
Original number is (10x + y).
If the digits interchange their position, the number becomes (10y + x).
Thus,
(10x + y) + 18 = (10y + x)
9x − 9y = − 18
x − y = − 2 .............(ii)
From (i), we get:
On substituting the value of y in (ii), we get:
⇒ x = 5 or x = − 7
Since the digits cannot be negative, x = 5 and
Hence, the required number = 10(5) + 7 = 57
OR
Let the smaller tap fill the tank in x hours.
Then, the larger tap will fill it in (x − 10) hours.
Time taken by both together to fill the tank = hours
Part filled by smaller tap in 1 hour =
Part filled by larger tap in 1 hour =
Part filled by both the taps in 1 hour =
∴
75(2x −10) = 8x(x −10) [By cross−multiplication]
⇒ 150x − 750 = 8x2 − 80x
⇒ 8x2 − 230x + 750 = 0
⇒ 4x2 − 115x + 375 = 0
⇒ 4x2 − 100x − 15x + 375 = 0 ⇒ 4x(x − 25) − 15(x − 25) = 0
⇒ (4x − 15)(x − 25) = 0 ⇒ (4x − 15) = 0 or (x − 25) = 0
⇒
⇒ x = 25
Hence, the time taken by the smaller tap to fill the tank = 25 hours.
And the time taken by the larger tap to fill the tank = (25 − 10) hours = 15 hours.