A two digit number is such that the sum of its digits is 4. If 18 is added to the number, it's digits are reversed. Find the number.
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Solution
let the number on one's position be y number on hundred's position be x we know 2 digit number be of form the form 10x+y given sum of number is 4 'that is x+y=4-------1
when 18 is added ,digit get reversed so 10x+y+18=10y+x (reverse of two digit nummber is 10x +y is 10y+x) 9x-9y=-18 x-y=-2(dividing by 2)------2
adding eqn 1 and eqn2 2x=2 x=1 sustitute in eqn1 1+y=4 y=3 so the number is 10x+y =10(1)+3 =13