Question

A two digit number such that the sum of itself and the number obtained when its digits are reversed is 70.
The simplest possible equation is

• A. $x+11y=70$
• B. $9x+11y=70$
• C. $11x+11y=70$
• D. $10x+10y=70$

Answer 1

The correct option is C $11x+11y=70$

Let, the unit digit of a number be $x$ and the ten digit of the same number be $y$.
so, the number is $10y+x$
and the reverse number is $10x+y$
ATQ,
$(10y+x)+(10x+y)=70$
So, the possible equation is $11x+11y=70$