A U shaped tube of mass '2m' is placed on a smooth horizontal surface. Two identical spherical balls each of mass 'm' and of diameter slightly less than the inner diameter of tube enters into the tube with a velocity u as shown. (Assume no loss of energy anywhere and all collisions to be elastic).
Speed of each spherical ball, just before their collision is
Let, velocity of tube becomes V along x direction just before collision, then velocities of balls will also be
V in this direction along with components of velocities perpendicular to this direction just before
collision. Apply conservation of momentum along X direction.
2mu = 2mV + mV + mV ⇒ V = u2
Apply Conservation of energy:
(12mu2) × 2 = 12(2m)V2 + 2[12m(V2 + V2y)]
⇒ Vy = u√2
Vnet = √(u2)2 + (u√2)2 = u√32