Question

A U- tube of base length l filled with same volume of two liquids of densities p and 2p is moving with an acceleration 'a' on the horizontal plane. If the height difference between thr two surfaces (open to atmosphere) becomes zero, then the height h is given by

• A. $\frac{3a}{2g}$
• B. $\frac{a}{2g}t$
• C. $\frac{a}{g}$
• D. $\frac{3al}{2g}$

Answer 1

The correct option is D $\frac{3al}{2g}$

now from mechanism of fluid mechanics $P_0=$ atmospheric pressure

$2\rho gh+P_0=P_0+\rho gh+\rho al\frac{1}{2}+2\rho \cdot \frac{al}{2}$

$h=\frac{3al}{2g}$

correct option is $\left(D\right)$