Question

A U tube of length L contains a liquid. It is mounted on a horizontal turn table rotating with an angular speed o about one of the arms. The difference in height between the liquid column in the vertical arms will be:

• A. $\frac{{\omega }^2{L}^2}{2g}$
• B. $\frac{{\omega }^2}{2L}$
• C. $\frac{{\omega }^2}{2g}$
• D. $\frac{{\omega }^{2}g}{2L}$

Answer 1

The correct option is A $\frac{{\omega }^2{L}^2}{2g}$

$\text{we know that}$

$\text{difference between heights}$

$\Delta h=\frac{1}{2}\frac{L^2{\omega }^2}{g}$

$\text{Answer:-(A)}$