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Question

A uniform chain has a mass M and length L. It is placed on a frictionless table with length L0 hanging over the edge. The chain begins to slide down. Then, the speed v with which the end slides down from the edge is given by
 


A
v=gL(L+L0)
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B
v=gL(LL0)
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C
v=gL(L2L20)
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D
v=2g(LL0)
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Solution

The correct option is C v=gL(L2L20)
Decrease in gravitational PE = increase in kinetic energy

or {MLL0gL02}{MgL2}=12Mv2
or v=gL(L2L20)

Physics

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