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Question

A uniform chain of length 2 m and mass 0.1 kg overchangs a smooth table with its two third part lying on the table. Find the kinetic energy of the chain as it completely slips-off the table.

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Solution

W=mgl2n2

Here 23th part is lying on the table it means 13this hanging

Remember n should always be greater than 1

Here n is 3

So W=mgl18

Now W=kinetic energy


W=mgl18=0.1×9.81×218=0.10



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