A uniform chain of length 2m is kept on a table such that a length of 60cm hangs freely from the edge of the table. The total mass of the chain is 4kg. What is the work done in pulling the entire chain on the table
Now,
Work done in pulling the chain on the table
As we know if we pull the chain, each part of the chain will not cover same height, therefore will not contribute the same potential energy, so let's take mass of the chain L′=L2n
Now we can write
W = mgL2n2
AFter putting all the values and solving
= 4×10×22×(103)2 = 3.6J
Hence the work done in pulling the chain is 3.6 J