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Question

# A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, work required to pull the hanging part on to the table is:

A
MgL
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B
MgL3
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C
MgL9
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D
MgL18
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Solution

## The correct option is D MgL18The weight of hanging part (L3) of chain is (13Mg). This weight acts at centre of gravity of the hanging part, which is at a distance of (L6) from the table.As work done =force×distance∴W=Mg3×L6=MgL18.

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