A uniform chain of length $l$ and mass $m$ overhangs a smooth table with its two third part lying on the table. Then the kinetic energy of the chain will be $^{'} x^{'} m g l$ then the value of $^{'} x^{'}$ will be (it completely slips off the table)

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Solution

This chain system can be converted into simple system as shown blow

$m / 3$ can go down if and only if surface is frictionless.
Change in potential energy is going to increase the kinetic energy of the system. So now we have to calculate the potential energy of the system.

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A uniform chain of length l and mass m overhangs a smooth table with its two third part lying on the table. Then the kinetic energy of the chain will be ′x′mgl then the value of ′x′ will be (it completely slips off the table)

This chain system can be converted into simple system as shown blow m/3 can go down if and only if surface is frictionless. Change in potential energy is going to increase the kinetic energy of the system. So now we have to calculate the potential energy of the system.

A uniform chain of length $l$ and mass $m$ overhangs a smooth table with its two third part lying on the table. Then the kinetic energy of the chain will be $^{'} x^{'} m g l$ then the value of $^{'} x^{'}$ will be (it completely slips off the table)

This chain system can be converted into simple system as shown blow

$m / 3$ can go down if and only if surface is frictionless.
Change in potential energy is going to increase the kinetic energy of the system. So now we have to calculate the potential energy of the system.