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Question

A uniform chain of length L hangs partly from a table which is kept in equilibrium by friction. The maximum length that can stand without slipping is l, then the coefficient of friction between the table and the chain is:

A
l2Ll
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B
lL
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C
lLl
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D
Lll
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Solution

The correct option is C lLl
Mass per unit length of the chain =ML
Mass of the hanging part =l(ML)
Mass of the part on the table =(Ll)(ML)
Force equation is:
μML(Ll)g=ML(l)g
μ=lLl

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