Question

A uniform chain of length L has one of its end attached to the wall at point A, while $\frac{3L}{4}$of the length of the chain is lying on table as shown in figure. The minimum co-efficient of friction between table and chain so that chain remains in equilibrium is

• A. $\frac{1}{3}$
• B. $\frac{1}{4}$
• C. $\frac{3}{4}$
• D. $\frac{1}{5}$

Answer 1

The correct option is B $\frac{1}{4}$

$Fcos{37}^{\circ }=\frac{\lambda L}{4}g$



$Fsin{37}^{\circ }=T=f\le \mu N$

$\Rightarrow \mu \ge \frac{1}{4}$
$\Rightarrow {\mu }_{min}=\frac{1}{4}$

$\left(where\lambda isthe\frac{mass}{length}ofthechain\right)$