Question

# A uniform chain of length l is placed on the table in such a manner that length l′ of it is hanging over the edge of the table without the chain sliding. If the coefficient of friction between the chain and the table is μ then find the maximum length of chain l′ that can hang without the entire chain slipping.

A

0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

(μ+1)lμ

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

lμ+1

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

μl1+μ

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D μl1+μ Assume the mass of the chain to be M kg. The linear density of the chain is given by π=Ml The mass of chain hanging is πl′ kg and the mass of chain on the table is π(l−l′) kg. The only force pulling the chain on the table is the weight of the chain that is hanging. For maximum hanging length without sliding, fmax=πl′g and fmax=μN=μπ(l−l′)g ⇒πl′g=μπ(l−l′)g ⇒l′=μl1+μ

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Work done by the force of gravity
PHYSICS
Watch in App
Explore more
Join BYJU'S Learning Program