A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, the work required to pull the hanging part on the table is
A
MgL
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B
MgL3
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C
MgL9
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D
MgL18
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Solution
The correct option is DMgL18 Mass M3 has its centre of mass L6 below the table surface. ∴W = mgh=(M3)(g)(L6) =MgL18