A uniform circular disc of mass 200 g and radius 4.0 cm is rotated about one of its diameter at an angular speed of 20 rad/s. Find its angular momentum about the axis of rotation.
A
160×10−5 rad/s
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B
8.0×10−5 rad/s
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C
4.0×10−5 rad/s
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D
10×10−5 rad/s
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Solution
The correct option is A160×10−5 rad/s The moment of inertia of the circular disc about its diameter is I=14Mr2=14(0.200kg)(0.04m)2 =8.0×10−5kg−m2. and the angular momentum about the axis of rotation is L=Iω=(8.0×10−5kg−m2)(20rad/s)