wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A uniform circular disc of mass M and radius a is given. A part of the radius b is removed from it. The distance between centre of original disc and circular hole's centre is c. The new position of C.M. from O is:

A
bcab
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
b2ba
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
b2ca2b2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
b2ca2+b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C b2ca2b2
σ=mπa2πb2
=mπ(a2b2)
Mass of whole disc
=mπ(a2b2)×πa2
=ma2(a2b2)
and mass of hole =mπ(a2b2)×πb2
=mb2(a2b2)
C.M. ma2(a2b2)×0mb2×ca2b2m=b2c(a2b2)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integrating Solids into the Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon