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Question

A uniform current carrying ring of mass m and radius R is connected by a massless string as shown in the figure. A uniform magnetic field B0 exists in the region to keep the ring in horizontal position, then the current in the ring is (l= length of string)


A
mgπRB0
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B
mgRB0
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C
mgπRB0
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D
mglπR2B0
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Solution

The correct option is C mgπRB0
Torque due to magnetic field τmag=MB0=IπR2B0
Torque due to weight about the point where string is connected
τweight=mgR
If ring remains horizontal , then τmag=τweight
IπR2B0=mgR
I=mgπRB0

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