Question

A uniform disc of mass $M$ and radius $R$ is mounted on an axle supported in frictionless bearings. A light cord is wrapped around the rim of the disc and a steady downward pull $T$ is exerted on the cord. The tangential acceleration of a point on the rim is

• A. $\frac{T}{M}$
• B. $\frac{MR}{T}$
• C. $\frac{2T}{MR}$
• D. $\frac{MR}{2T}$

Answer 1

The correct option is C $\frac{2T}{MR}$

$\Rightarrow \alpha =\frac{Tosaue}{M.I}$

$=\frac{T.R2}{M{R}^2}$

$=\frac{2T}{MR}.$

Hence, the answer is $\frac{2T}{MR}.$