A uniform disc of mass M and radius R is released from the shown position. PQ is a string, OP is a horizontal line, O is the centre of the disc and distance OP is R/2 . Then tension in the string just after the disc is released will be:

$\frac{M g}{2}$

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$\frac{M g}{3}$

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$\frac{2 M g}{3}$

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None of these

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Solution

The correct option is C
$\frac{2 M g}{3}$

Let a is the cceleration of center of mass & α is the angular acceleration of body about center of mass. Applying Newton's law on centre of mass O

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Q. A uniform disc of mass

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and radius

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is released from rest in the shown position.

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is a horizontal line,

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Q. A uniform disc of mass

M

and radius

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is released from the shown position.

P Q

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. Find the tension in the string just after the disc is released .

A uniform disc of mass $M$ and radius $R$ is released from the shown position. $P Q$ is a string, $O P$ is a horizontal line, $O$ is the centre of the disc and distance $O P$ is $\frac{R}{2}$ . Then tension in the string just after the disc is released will be: