wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

A uniform disc of radius R/2 is put over another uniform disc of radius R of same thickness and density. The peripheries of the two disc touch each other. The centre of mass of the system is from centre of big disc

Open in App
Solution

Let σ is mass per unit area.

Mass of disc of radius R is M1=σ×A1=σ×πR2

Mass of disc of radius R/2 is M2=σ×A2=σ×πR24

Let the centre of the disc of radius R be at the origin. The arrangement is shown in the figure below.


We know that,
Centre of mass = xcm=M1x1+M2x2M1+M2

xcm=σπR2×0+σπR24×R2σ×πR2+σ×πR24

xcm=R10

Hence, xcm=R10 right to the centre of the big disc.


flag
Suggest Corrections
thumbs-up
47
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Centre of Mass in Galileo's World
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon