A uniform electric field of magnitude $100 V / m$ in space is directed along the line $y = 3 + x$ . Find the electric potential difference between $(1, 3)$ and $(3, 1)$ .

100 V

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200 \sqrt{2} V

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200 V

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0

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Solution

The correct option is D $0$
Given electric field, $E = 100 V / m$ directed along line $y = 3 + x$
We have to find the electric potential difference between $(1, 3)$ and $(3, 1)$ .
We know that the potential difference $V$ is related to electric field $E$ by the relation, $E = \frac{- d V}{d r}$
or, $d V = - E d r$
So, potential difference between the points $(3, 1)$ and $(1, 3)$ is:
$d V = - 100 (1 - 3) - 100 (3 - 1) = 0 V$

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A uniform electric field of magnitude 100V/m in space is directed along the line y=3+x. Find the electric potential difference between (1,3) and (3,1).

A uniform electric field of magnitude $100 V / m$ in space is directed along the line $y = 3 + x$ . Find the electric potential difference between $(1, 3)$ and $(3, 1)$ .