Question

A uniform electric field of magnitude $325V{m}^{-1}$ is directed in negative z direction. Coordinates of point A are ($2m,3m$) and those of point B are ($4m,5m$). Calculate the work done in bringing a unit positive charge along the given path.

• A. $2600J$
• B. $3250J$
• C. $5200J$
• D. zero

Answer 1

The correct option is A $2600J$



Work done in moving the charge from C to B = 0
(since path is perpendicular to the electric field)

Work done in moving the charge from A to C
$W=q(V_f-V_i)=q(V_C-V_A)=q\Delta V$

Here, $\Delta V=$ Electric field $\times$ distance between A and C
$=325V/m\times 8m=2600V$

Hence, work done $W=q\Delta V=2600J$